A bar magnet of magnetic moment $M$ is bent into a semicircle. The new magnetic moment is:

The magnetic field due to a small magnetic dipole of magnetic moment $M$, at distance $r$ from the centre on the equatorial line is given by (in M.K.S system)

The distance of two points on the axis of a magnet from its centre is $10\;cm$ and $20\;cm$ respectively. The ratio of magnetic intensity at these points is $12.5\;:1$. The length of the magnet will be

Direction of magnetic field at equatorial point is

Inside a bar magnet, the magnetic field lines travel from:

The points $A\;{\rm{and}}\;B$ are situated perpendicular to the axis of 2 cm long bar magnet at large distances $x$ and 3$x$ from the centre on opposite sides. The ratio of magnetic fields at $A\;{\rm{and}}\;B$ will be approximately equal to

The magnetic field due to short bar magnet of magnetic dipole moment $M$ and length $2l,$ on the axis at a distance $z$ (where $z\; > > l$) from the center of the magnet is given by formula

A short bar magnet is placed with its north pole pointing towards geographic north. The neutral point is located:

The needle of a deflection galvanometer shows a deflection of $60^\circ$ due to a short bar magnet at a certain distance in tan $A$ position. If the distance is double the deflection is

A short bar magnet of magnetic moment 255 ${\rm{J}}{{\rm{T}}^{ - 1}}$ is placed with its axis perpendicular to earth’s field direction. At what distance from the center of the magnet, the resultant field is inclined at $45^\circ$ with earth’s field, $H = 0.4 imes {10^{ - 4}}{\rm{\;T\;}}?$

Due to a small magnet, intensity at a distance $x$ in the end on position is $9\;gauss$. What will be the intensity at a distance $\frac{x}{2}$ on broad side on position