A small bar magnet has a magnetic moment $1.2\;A$-${m^2}.$ The magnetic field at a distance $0.1\;m$ on it axis will be: $({\mu _0} = 4\pi imes {10^{ - 7}}$-$m/A)$

The distance of two points on the axis of a magnet from its centre is $10\;cm$ and $20\;cm$ respectively. The ratio of magnetic intensity at these points is $12.5\;:1$. The length of the magnet will be

The magnetic field is strongest at which point of a bar magnet?

The magnetic field of a small bar magnet varies in the following manner by the influence of a magnet placed at a large distance $d$.

A bar magnet is cut into two equal pieces along its length. The magnetic moment of each piece becomes:

Two identical short bar magnets are placed at a distance $d$ apart with their axes perpendicular to each other. The magnetic field at the midpoint of the line joining their centers is:

The deflection magnetometer is most sensitive when deflection ${\rm{heta }}$ is

Ratio of magnetic intensities for an axial point and a point on broad side-on position at equal distance $d$ from the centre of magnet will be or The magnetic field at a distance $d$ from a short bar magnet in longitudinal and transverse positions are in the ratio

A short bar magnet of magnetic moment 255 ${\rm{J}}{{\rm{T}}^{ - 1}}$ is placed with its axis perpendicular to earth’s field direction. At what distance from the center of the magnet, the resultant field is inclined at $45^\circ$ with earth’s field, $H = 0.4 imes {10^{ - 4}}{\rm{\;T\;}}?$

A short magnet of moment $6.75\;A{m^2}$ produces a neutral point on its axis. If horizontal component of earth’s magnetic field is $5 imes {10^{ - 5}}Wb/{m^2}$, then the distance of the neutral point should be

A bar magnet is $10\;cm$ long, and is kept with its north (N)- pole pointing north. A neutral point is formed at a distance of $15\;cm$ from each pole. Given the horizontal component of earth’s field to be 0.4 Gauss, the pole strength of the magnet is