The magnetic field due to a small magnetic dipole of magnetic moment $M$, at distance $r$ from the centre on the equatorial line is given by (in M.K.S system)

The points $A\;{\rm{and}}\;B$ are situated perpendicular to the axis of 2 cm long bar magnet at large distances $x$ and 3$x$ from the centre on opposite sides. The ratio of magnetic fields at $A\;{\rm{and}}\;B$ will be approximately equal to

Two identical short bar magnets, each of magnetic moment $M$, are placed perpendicular to each other at a distance $d$ apart. The magnetic field at a point midway between them on the line joining their centers is:

The magnetic field of a small bar magnet varies in the following manner by the influence of a magnet placed at a large distance $d$.

The magnetic field due to a small magnetic dipole of magnetic moment $M$, at distance $r$ from the centre on the equatorial line is given by (in M.K.S system)

A short bar magnet is placed with its north pole pointing towards geographic north. The neutral point is located:

Breaking a bar magnet in half results in:

Force between two identical short bar magnets whose centers are $r$ metre apart is 8.1 N, when their axes are along the same line. If separation is increased to 3 $r$ and the axis are rearranged perpendicularly, the force between them would become

A short magnet of moment $6.75\;A{m^2}$ produces a neutral point on its axis. If horizontal component of earth’s magnetic field is $5 imes {10^{ - 5}}Wb/{m^2}$, then the distance of the neutral point should be

A bar magnet is $10\;cm$ long, and is kept with its north (N)- pole pointing north. A neutral point is formed at a distance of $15\;cm$ from each pole. Given the horizontal component of earth’s field to be 0.4 Gauss, the pole strength of the magnet is

The magnetic potential at a point on the axial line of a bar magnet of dipole moment $M$ is $V$. What is the magnetic potential due to a bar magnet of dipole moment $\frac{M}{4}$ at the same point