Three liquids of densities ${\rho _1},{\rho _2}$ and ${\rho _3}$ (with ${\rho _1} > {\rho _2} > {\rho _3}$), having the same value of surface tension T, rise to the same height in three identical capillaries. The angles of contact ${heta _1},{heta _2}\,$ and ${heta _3}$ obey

A water film is formed between two parallel wires of 10 cm length. The distance of 0.5 cm between the wires is increased by 1 mm. Which will be the work done? (Surface tension of water =  $72{\rm{N}}{{\rm{m}}^{ - 1}})$

A river of salty water if flowing with a velocity $2{\rm{m}}{{\rm{s}}^{ - 1}}$. If the density of the water is $1.2{\rm{gc}}{{\rm{c}}^{ - 1}}$, then the kinetic energy of each cubic meter of water is

A capillary tube of radius $r$ is immersed in water. The water rises to a height $h$, and the mass of water in the tube is $m$. Which of the following expressions correctly represents the mass of water that would rise in a tube of radius $2r$ immersed in the same water?

The rise of liquid in a capillary tube of radius $r$ is $h$ due to surface tension. If diameter of the tube is reduced to half, then rise of level in the tube will be

A water film is made between two straight parallel wires of length 10 cm separated by 5 mm from each other. If the distance between the wires is increased by 2 mm. How much work will be done? Surface tension for water is $72{\rm{dyne c}}{{\rm{m}}^{ - 1}}$

The radius of a soap bubble is increased from $\frac{1}{{\sqrt \pi }}\,cm\,\,to\,\,\frac{2}{{\sqrt \pi }}\,\,cm$. If the surface tension of water is 30 dynes per cm, then the work done will be

Determine the energy stored in the surface of a soap bubble of radius 2.1 cm if its surface tension is $4.5 imes {10^{ - 2}}{\rm{N}}{{\rm{m}}^{ - 1}}$

Two liquid drops have diameters of 1 cm and 1.5 cm. The ratio of excess of pressure inside them is

If the length of tube is less and cannot accommodate the maximum rise of liquid then

A sphere liquid drop of radius $R$ is divided into eight equal to droplets. If surface tension is $T$, then the work done in this process will be