A viscous liquid flows through a horizontal pipe of varying cross-section. At point A, the radius is 'r' and the velocity is 'v'. At point B, the radius is 'r/2'. Ignoring any energy losses due to viscosity, what is the pressure difference between points A and B?

Poiseuille's equation is valid for which type of flow?

According to Poiseuille's equation, the rate of flow of a liquid through a narrow tube is directly proportional to which power of the radius of the tube?

When an air bubble of radius r rises from the bottom to the surface of a lake, its radius becomes $\frac{{5r}}{4}$. Taking the atmospheric pressure to be equal to 10 m height of water column, the depth of the lake would approximately be (ignore the surface tension and the effect of temperature)

If the length of a tube is doubled, while keeping all other factors constant, how will the flow rate of a liquid through the tube change according to Poiseuille's equation?

The level of water in a tank is 5 m high. A hole of area $10{\rm{c}}{{\rm{m}}^2}$ is made in the bottom of the tank. The rate of leakage of water from the hole is

Poiseuille's equation is most accurate for describing fluid flow in which scenario?

If the velocity head of a stream of water is equal to 10 cm, then its speed of flow is (${\rm{g}} = 10{\rm{m}}{{\rm{s}}^{ - 2}}$)

Two capillaries of same length and radii in the ratio $1:2$ are connected in series. A liquid flow through Them in streamlined condition. If the pressure across the two extreme ends of the combination is $1m$ of water, the pressure difference across first capillary is

The radius of a blood vessel is doubled. Assuming all other factors remain constant, according to Poiseuille's equation, the rate of blood flow through the vessel will become:

A water tank, open to the atmosphere, has a leak in it, in the form of a circular hole, located at a height h below the open surface of water. The velocity of the water coming out of the hole is