NEET Chemistry Structure Of Atom Oblique Projectile MCQs

A man desires to swim across a river through shortest distance the velocity of river water is $3\,Km\,{h^{ - 1}}$. He can swim in still water at $6Km\,{h^{ - 1}}$. At what angle with the velocity of flow of river should he swim?

A man desires to swim across a river through shortest distance the velocity of river water is $3\,Km\,{h^{ - 1}}$. He can swim in still water at $6Km\,{h^{ - 1}}$. At what angle with the velocity of flow of river should he swim?

The kinetic energy of a projectile becomes half of its initial kinetic energy at maximum height. The maximum height of the projectile is ($u o$initial velocity)

The kinetic energy of a projectile becomes half of its initial kinetic energy at maximum height. The maximum height of the projectile is ($u o$initial velocity)

The equation of trajectory of projectile is $y = \sqrt 3 x - \frac{g}{2}{x^2}$ the horizontal range for projectile is

The equation of trajectory of projectile is $y = \sqrt 3 x - \frac{g}{2}{x^2}$ the horizontal range for projectile is

A ball is projected from ground at angle $heta$ with the horizontal. After t=1s, it is moving at ${45^0}$ with the horizontal and after t=2second, it is moving horizontally. What is speed of projection of ball ? $\left[ {g = 10{\rm{ }}m{s^{ - 2}}} \right]$

A ball is projected from ground at angle $heta$ with the horizontal. After t=1s, it is moving at ${45^0}$ with the horizontal and after t=2second, it is moving horizontally. What is speed of projection of ball ? $\left[ {g = 10{\rm{ }}m{s^{ - 2}}} \right]$

A man is swimming with speed 10 km/h in still water crosses a river of width 1 km along the shortest path in 10 minutes. The velocity of river flow is

A man is swimming with speed 10 km/h in still water crosses a river of width 1 km along the shortest path in 10 minutes. The velocity of river flow is