A force is inclined at ${60^0}$ to the horizontal. If its rectangular component in the horizontal direction is 50 N, then magnitude of the force in the vertical direction is

The angle between the two vectors $\overrightarrow A = \widehat i + 2\widehat j - \widehat k\,and\,\overrightarrow B = - \widehat i + \widehat j - 2\widehat k$ is

Vector $\vec A$ has magnitude of 5 unit directed along east, then vector $6\vec A$

A force is inclined at ${60^0}$ to the horizontal. If its rectangular component in the horizontal direction is 50 N, then magnitude of the force in the vertical direction is

A vector ${\rm{\vec A}}$ when added to the vector ${\rm{\vec B = }}3\hat i + 4\hat j$ yields a resultant vector that is in the positive y direction and has a magnitude equal to that of ${\rm{\vec B}}$ Find the magnitude of ${\rm{\vec A}}$

$\overrightarrow A \,.\,\overrightarrow B = - \left| A \right|\left| B \right|$, then

If the resultant of the vectors $\left( {\hat i + 2\hat j - \hat k} \right),\left( {\hat i - \hat j + 2\hat k} \right)$ and ${\rm{\vec C}}$ is a unit vector along the y-direction, then ${\rm{\vec C}}$ is

A force is inclined at ${60^0}$ to the horizontal. If its rectangular component in the horizontal direction is 50 N, then magnitude of the force in the vertical direction is

Find the vector component of vector $\overrightarrow A = 2\widehat i + 3\widehat j$ along the direction of $\overrightarrow B = \widehat i + \widehat j$

A vector ${\rm{\vec A}}$ when added to the vector ${\rm{\vec B = }}3\hat i + 4\hat j$ yields a resultant vector that is in the positive y direction and has a magnitude equal to that of ${\rm{\vec B}}$ Find the magnitude of ${\rm{\vec A}}$

A force is inclined at ${60^0}$ to the horizontal. If its rectangular component in the horizontal direction is 50 N, then magnitude of the force in the vertical direction is