The position coordinates of a particle moving in X-Y as a function of time t are $\;\;x = 2{t^2} + 6t + 25\,,\,y = {t^2} + 2t + 1$ The speed of the object at t=10 s is approximately

A particle is moving in a straight line with velocity (v) = (t – 4) m/s. What is the average speed between t = 0 to t = 8 second?

A car moves from X to Y with a uniform speed ${v_u}$ and returns to Y with a uniform speed ${v_d}$. The average speed for this round trip is

A body movies with an initial velocity $10\,\,m{s^{ - 1}}$. . If it covers a distance of 20 m in 2S, then acceleration of the body is

An aeroplane files around a square field ABCD of each side 1000 km. Its speed along AB is $250\;km\;{h^{ - 1}}$, along DA $100\;km\;{h^{ - 1}}$. Its average speed (in $km\;{h^{ - 1}}$)) over the entire trip is

A car runs at a constant speed on a circular track of radius 100 m, taking 62.8 s for every circular lap. The average velocity and average speed for each circular lap is

Percentage of total distance covered in 5th Second by a freely falling body is

The velocity ‘V’ of a moving object varies with displacement ‘x’ as $v = 3{x^2} - 2x$ , then the value of acceleration at x = 2 m is

A car travels 20 m in 2 seconds and 40 m in the next 4 seconds. What is its average acceleration?

A drone's horizontal and vertical positions are given by $x = 6t - t^2$ and $y = 4t$, respectively (in meters and seconds). At what time is the drone's vertical acceleration equal to zero?

Two cars $P$ and $Q$ starts from a point at the same time in a straight line and their positions are represented by ${x_p}(t) = at + b{t^2}$ and ${x_Q}(t) = ft - {t^2}$. At what time do the cars have the same velocity