Related Questions

    4.

    Two boys are standing at the ends A and B of a ground where AB=a. The boy at B starts running in a direction perpendicular to AB with velocity v1{v_1}. The boy at A starts running simultaneously with velocity v and catches the other boy in a time t, when t is

    A

    a(v2+v12)\frac{a}{{\sqrt {\left( {{v^2} + v_1^2} \right)} }}

    B

    a2β€…β€Š/β€…β€Š(v2βˆ’v12)\sqrt {{a^2}\;/\;\left( {{v^2} - v_1^2} \right)}

    C

    aβ€…β€Š/β€…β€Š(vβˆ’v1)a\;/\;\left( {v - {v_1}} \right)

    D

    aβ€…β€Š/β€…β€Š(vβ€…β€Š+v1)a\;/\;\left( {v\; + {v_1}} \right)

    Question Tags

    company logo