A stone falls from a balloon that is descending at a uniform rate of $12{\rm{m}}{{\rm{s}}^{ - 1}}$. The displacement of the stone from the point of release after 10s is

A stone falls from a balloon that is descending at a uniform rate of $12{\rm{m}}{{\rm{s}}^{ - 1}}$. The displacement of the stone from the point of release after 10s is

A particle when thrown, moves such that it passes from same height at 2 and 10s, the height is

A horizontal line on a velocity-time graph indicates:

At t=0, a stone of mass 10 gm is thrown straight up from the ground level with a speed 10 m/s. After 1 s, a second stone of the same mass is thrown from the same position with a speed 20 m/s. What is the position of the first stone from the ground level at that moment? (Take ${\rm{g}} = 10\;m/{s^2}$)

A stone dropped from a balloon which is at a height h, reaches the ground after t second. From the same balloon, if two stones are thrown, one upwards and the other downwards, with the same velocity u and they reach the ground after ${t_1}$ and ${t_2}$ second respectively, then

A body is thrown vertically up from the ground. It reaches a maximum height of 100m in 5sec. After what time it will reach the ground from the maximum height position

A projectile is fired vertically upwards with an initial velocity u. After an interval of T seconds a second projectile is fired vertically upwards, also with initial velocity is

A body of mass 3 kg falls from the multi-storeyed building 100m high and buries itself 2m deep in the sand. The time of penetration will be

A man throws a ball vertically upwards and it rises through 20 m and returns to his hands. What was the initial velocity (u) of the ball and for how much time (T) it remained in the air? $\left( {{\rm{g}} = 10{\rm{\;m}}{{\rm{s}}^{ - 2}}} \right)$

A body falling from a high Minaret travels 40 m in the last 2 seconds of its fall to ground. Height of Minaret in meters is (take $g = 10\;m/{s^{ - 2}}$ )