NEET Physics MCQ: NCERT Motion in Straight Line

🔄Ncert Concepts :Work, Energy, Power, Graphs

Related Questions

A ball thrown upward from the top of a tower with speed v reaches the ground in ${t_1}$ second. If this ball is thrown downward from the top of he same tower with speed v it reaches the ground in ${t_2}$ second. In what time the ball shall reach the ground if it is allowed to falls freely under gravity from the top of the tower?

$\frac{{{t_1} + {t_2}}}{2}$

$\frac{{{t_1} - {t_2}}}{2}$

$\sqrt {{t_1}{t_2}}$

${t_1} + {t_2}$

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🎓 Ncert Level:Analyzing

🔄Ncert Concepts :kinematics, equations of motion, projectile motion

A stone dropped from a building of height h and it reaches after t seconds on earth. From the same building if two stones are thrown (one upwards and other downwards) with the same velocity u and they reach the earth surface after ${t_1}$ and ${t_2}$ seconds respectively, then

$t = {t_1} - {t_2}$

$t = \frac{{{t_1} + {t_2}}}{2}$

$t = \sqrt {{t_1}{t_2}}$

$t = t_1^2t_2^2$

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🎓 Ncert Level:Analyzing

🔄Ncert Concepts :kinematics, equations of motion, projectile motion

At t=0, a stone of mass 10 gm is thrown straight up from the ground level with a speed 10 m/s. After 1 s, a second stone of the same mass is thrown from the same position with a speed 20 m/s. What is the position of the first stone from the ground level at that moment? (Take ${\rm{g}} = 10\;m/{s^2}$ )

10 m

1 m

2 m

5 m

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🔄Ncert Concepts :kinematics, projectile motion, uniformly accelerated motion

From the top of a tower of two stones, whose masses are in the ratio 1 : 2 are thrown on straight up with an initial speed u and the second straight down with the same speed u. Then neglecting air resistance

The heavier stone hits the ground with a higher speed

The lighter stone hits the ground with a higher speed

Both the stones will have the same speed when they hit the ground

The speed can’t be determined with the given data

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🔄Ncert Concepts :conservation of energy, kinematics

A body is thrown vertically up from the ground. It reaches a maximum height of 100m in 5sec. After what time it will reach the ground from the maximum height position

$1.2\,\sec$

5 sec

10 sec

25 se

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🔄Ncert Concepts :projectile motion, free fall, time of flight

A particle starts from rest and moves with a varying acceleration as shown in the graph. If the particle's velocity at $t=4$ s is $v$ , its velocity at $t=8$ s will be:

8 m/s

0 m/s

4 m/s

-8 m/s

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🔄Ncert Concepts :Kinematics, Graphs, Calculus

A stone falls freely from rest from a height h and it travels a distance $\frac{{9h}}{{25}}$ in the last second. The value of h is

145 m

100 m

122.5 m

200 m

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🔄Ncert Concepts :kinematics, free fall, equations of motion

A projectile is fired vertically upwards with an initial velocity u. After an interval of T seconds a second projectile is fired vertically upwards, also with initial velocity is

They meet at time $t = \frac{u}{g}$ and at a height $\frac{{{u^2}}}{{2G}} + \frac{{g{T^2}}}{8}$

They meet at time $t = \frac{u}{g} + \frac{T}{2}$ and at a height $\frac{{{u^2}}}{{2g}} + \frac{{g{T^2}}}{8}$

They meet at time $t = \frac{u}{g} + \frac{T}{2}$ and at a height $\frac{{{u^2}}}{{2g}} - \frac{{g{T^2}}}{8}$

They never meet

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🎓 Ncert Level:Analyzing