If a simple pendulum is taken to the moon, its time period will:

The angular velocities of three bodies in simple harmonic motion are ${\omega _1},\,\,{\omega _2},\,\,{\omega _3}$ with their respective amplitudes as ${A_1},\,\,{A_2},\,\,{A_3},.$ If all the bodies have same mass and velocity, then

A simple pendulum of length $L$ has a time period $T$. If the length is increased by $\Delta L$ such that $\Delta L << L$, the change in time period $\Delta T$ is approximately:

A mass attached to a spring oscillates horizontally. Its acceleration is $25 \, m/s^2$ when it is 10 cm from its equilibrium position. Find the period of oscillation.

If a simple pendulum of length l has maximum angular displacement θ, then the maximum kinetic energy of bob of mass m is

For a simple pendulum the graph between L and T will be

A man measures the period of a simple pendulum inside a stationary lift and finds it to be $T$ second. If the lift accelerates upwards with an acceleration g/4, then the period of pendulum will be

A simple pendulum having a bob of mass 100 grams is oscillating with a maximum angular displacement of ${3^0}$. The maximum restoring force acting on the bob is $\left[ {{\rm{take}}\,\,g = 10\,\,m/{s^2}} \right]$

If a simple harmonic is represented by \frac{{{d^2}x}}{{d{t^2}}}$$ + \alpha x = 0,its time period is

The amplitude of an oscillating simple pendulum is 10cm and its period is 4 s. Its speed after 1 s after it passes its equilibrium position, is

A tunnel is made across the earth of radius $R$, passing through its centre. A ball is dropped from a height h in the tunnel. The motion will be periodic with time period.