The time period of a simple pendulum, when it is made to oscillate on the surface of moon

A rectangular block of mass m and area of cross-section A floats in a liquid of density ρ. If it is given a small vertical displacement from equilibrium it undergoes oscillation with a time period T. Then

A particle executes harmonic motion with an angular velocity and maximum acceleration of $3.5\;\,\,rad/s$ and $\;7.5\,\,m/{s^2}$ respectively. The amplitude of oscillation is

A body has a time period ${T_1}$ under the action of one force and ${T_2}$ under the action of another force, the square of the time period when both the forces are acting in the same direction is

The metallic bob of a simple pendulum has the relative density $\rho$.The time period of this pendulum is T. If the metallic bob is immersed in water, then the new time period is given by

Two simple pendulums, A and B, have lengths $L$ and $4L$ respectively. If the bob of pendulum A is displaced by a small angle $heta$ and released, what angle should the bob of pendulum B be displaced by to have the same maximum velocity as pendulum A?

A second’s pendulum is placed in a space laboratory orbiting around the earth at a height 3$R$, where $R$ is the radius of the earth. The time period of the pendulum is

The ratio of maximum acceleration to maximum velocity in a simple harmonic motion is $10{s^{ - 1}}$. At, t= 0 the displacement is 5m. What is the maximum acceleration? (The initial phase is $\frac{\pi }{4}$)

The periods of oscillations of a pendulum at two places are 1.4 S and 1.6 S. The ratio of two places are 1.4 S and 1.6 S. The ratio of the accelerations due to gravity at those two places

A seconds pendulum at the equator $\left[ {g = 9.8\,\,m/{s^2}} \right]$ is taken to the poles $\left[ {g = 9.83\,\,m/{s^2}} \right]$. If it is to act as second’s pendulum, its length should be

A mass attached to a spring oscillates horizontally. Its acceleration is $25 \, m/s^2$ when it is 10 cm from its equilibrium position. Find the period of oscillation.