A simple pendulum with a bob of mass $m$ and length $L$ is oscillating in a lift accelerating upwards with acceleration $a$. The effective acceleration due to gravity experienced by the pendulum is:

The time period of a simple pendulum of length $L$ at a place is $T$. Acceleration due to gravity at that place is

A plate oscillates with time period $'T'$. Suddenly, another plate put on the first time, then time period

The angular velocities of three bodies in simple harmonic motion are ${\omega _1},\,\,{\omega _2},\,\,{\omega _3}$ with their respective amplitudes as ${A_1},\,\,{A_2},\,\,{A_3},.$ If all the bodies have same mass and velocity, then

A block of mass $100\,g$ attached at the bottom of a light spring stretches it by $9.8\,cm$. If the block is further pulled down by $2\,cm$ and released, the frequency of its oscillation will be $\left[ {g = 9.8\,\,m/{s^2}} \right]$

A clock which keeps correct time at 20℃, is subjected to 40℃. If coefficient of linear expansion of the pendulum is $12 imes {10^{ - 6}}/^\circ C$. How much will it gain or loose in time

A pendulum oscillates in a clock. When the bob is 5 cm from its mean position, its acceleration is $20 \, m/s^2$. What is the time period of the pendulum?

A clock which keeps correct time at 20℃, is subjected to 40℃. If coefficient of linear expansion of the pendulum is $12 imes {10^{ - 6}}/^\circ C$. How much will it gain or loose in time

If the length of seconds pendulum is increased by 1% then the time lost by it per a day is

A pendulum clock that shows correct time on the surface of earth is taken to the surface of moon where ${g_{{\rm{moon}}}} = \frac{{{g_{{\rm{earth}}}}}}{6}$. The clock will run

If the length of a simple pendulum is increased by a factor of 4 and the mass of the bob is halved, how many times will the new time period be compared to the original time period?