A particle of 0.25 kg vibrates with a period of 2 second. If its greatest displacement is 0.4 m the maximum velocity in $m{s^{ - 1}}$ is

The height of a swing changes during its motion from 0.1 $m$ to 2.5 $m$. The minimum velocity of a boy who swings in this swing is

The displacement of a particle executing SHM is given by $y = 0.25{\rm{ }}sin{\rm{ }}200t{\rm{ }}\,\,\,cm$ the maximum speed of the particle is

A S.H.M. has amplitude $'a'$ and time period $T$.The maximum velocity will be

A particle executes linear SHM with an amplitude of $3$ cm. When the particle is at $2$ cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then, its time period in seconds is:

The equation of SHM is given by $x = 3\sin 20\pi t + 4\cos 20\pi t$ Where x is in cm and t is I second. The amplitude is

Starting from $y = A$ $\sin \,\,\omega t{\rm{ }}or{\rm{ }}y = A\,\,\cos \,\,\omega t$

The equation of SHM is given by $x = 3\sin 20\pi t + 4\cos 20\pi t$ Where x is in cm and t is I second. The amplitude is

The velocities of a body executing $SHM$ are $3\,cm/s$ and $4\,cm/s$. When the displacements are $4\,cm$ and $3\,cm$ respectively then period is

A particle executes S.H.M. with a period of 6 second and amplitude of 3 $cm$ . Its maximum speed in $cm$/$s$ is

A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in second is