A particle executes linear simple harmonic motion with an amplitude of When the particle is at from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is
Related Questions
Graph between velocity and displacement of a particle, executing S.H.M. is
A straight line
A parabola
A hyperbola
An ellipse
The phase difference between displacement and acceleration of a particle in a simple harmonic motion is:
zero
Two particles P and Q start from origin and execute Simple Harmonic Motion along X-axis with same amplitude but with period 3 seconds and 6 seconds respectively. The ratio of the velocities of P and Q when they meet is
In SHM, the amplitude is cm. At what displacement from the mean position will the magnitude of velocity be equal to half the maximum velocity, if at a certain displacement, the magnitudes of velocity and acceleration are equal?
3
3√2
3√3
6
A body executing simple harmonic motion has a maximum acceleration equal to and maximum velocity of ,the amplitude of the simple harmonic motion is
If the maximum acceleration of a is and the maximum velocity is , then the amplitude of vibration is
A particle moves in x-y plane according to rule x=a sinωt and y=a cosωt. The particle follows
Circular path
Parabolic path
Elliptical path
Straight line
A particle executing SHM has a maximum speed of cm/s and a maximum acceleration of m/s. Find the amplitude of oscillation.
cm
cm
cm
cm
A simple pendulum swings back and forth. What is its average velocity over one complete swing?
Zero
Maximum at the equilibrium position
Constant and non-zero
Dependent on the length of the pendulum