Which of the following materials generally has the highest Young's modulus?

A copper rod of length $L$ and radius $r$ is suspended from the ceiling by one of its ends. What will be elongation of the rod due to its own weight when $\rho \,\,{\rm{and}}\,Y$ are the density and Young’s modulus of the copper respectively?

The elastic limit of brass is $379MPa$. What should be the minimum diameter of a brass rod, if it is to support a $400N$ load without exceeding its elastic limit

A fixed volume of iron is drawn into a wire of length $L$. The extension $x$ produced in this wire by a constant force $F$ is proportional to

Two wires $A$ and $B$ have. Young’s moduli in the ratio $1:2$ and ratio of length is $1:1$. Under the application of same stress the ratio of elongations is.

If a force $F$ is applied to a wire of length $L$ and cross-sectional area $A$, causing it to stretch by $\Delta L$, which of the following expressions correctly represents the strain experienced by the wire?

There are two wires of same material and same length while the diameter of second wire is ${\rm{2}}$ times the diameter of first wire, then ratio of extension produced in the wires by applying same load will be

A rectangular bar $2\,\,cm$ in breadth and $1\,\,cm$ in depth and $100\,\,cm$ in length is supported at its ends and a load of $2$ kg is applied at its middle. If Young’s modulus of the material of the bar is $20\,\, imes \,\,{10^{11}}\,\,{\rm{dyne c}}{{\rm{m}}^{ - 2}},$, the depression in the bar is

A wire of length $L$ and cross-sectional area $A$ is subjected to a tensile stress $\sigma$. If the Poisson's ratio of the material is $

u$and Young's modulus is$Y$, the elastic potential energy stored per unit volume is:

If the compressibility of water is $\sigma$ per unit atmospheric pressure, then the decrease in volume ($V$)  due to p, atmospheric pressure will be :

What should be the lengths of a steel and copper rod at 0$^ \circ C$  so that the length of the steel rod is 5 cm longer than the copper rod at any temperature?$\alpha$ (Steel) = 1.1$imes {10^{ - 5}}^ \circ {C^{ - 1}}$ $\alpha ($Copper)= $1.7 imes {10^{ - 5}}^ \circ {C^{ - 1}}$