A thin uniform rod of mass MMM and length LLL is bent into a semicircle. A particle of mass mmm is placed at the center of the semicircle. The gravitational force exerted by the rod on the particle is:
GMmL2\frac{GMm}{L^2}L2GMm
2GMmL2\frac{2GMm}{L^2}L22GMm
πGMmL2\frac{\pi GMm}{L^2}L2πGMm
2πGMmL2\frac{2\pi GMm}{L^2}L22πGMm
Related Questions
A small disc of radius 2 cm is cut from a disc of radius 6 cm. If the distance between their centres is 3.2 cm, what is the shift in the centre of mass of the disc?
0.4 cm0.4\,cm0.4cm
2.4 cm2.4\,cm2.4cm
1.8 cm1.8\,cm1.8cm
1.2 cm1.2\,cm1.2cm
