A thermocouple using iron and copper produces an emf of when its junctions are kept at and . If the cold junction is kept at and the emf is , what is the temperature of the hot junction?
\frac{100E_2}{E_1} - 20
\frac{100E_1}{E_2} - 20
\frac{100E_2}{E_1} + 20
\frac{E_2}{E_1} + 20
Related Questions
The freezing point on a thermometer is marked as and the boiling point as . A temperature of on this thermometer will be read as
20
400/13
100/13
60
The freezing point on a thermometer is marked as and the boiling point as . A temperature of on this thermometer will be read as
A thermocouple using iron and copper produces an emf of when its junctions are kept at and . If the cold junction is kept at and the emf is , what is the temperature of the hot junction?
\frac{100E_2}{E_1} - 20
\frac{100E_1}{E_2} - 20
\frac{100E_2}{E_1} + 20
\frac{E_2}{E_1} + 20
A constant volume gas thermometer shows pressure readings of at the triple point of water and at the boiling point of water at 1 atm. What is the ideal gas temperature corresponding to a pressure reading of ?
273.16 K
373.15 K
546.32 K
646.3 K
A platinum resistance thermometer has a resistance of at and at . If its resistance is measured to be when placed in a hot bath, what is the temperature of the bath, assuming a linear relationship between resistance and temperature?
60°C
70°C
80°C
90°C