The time period of a simple pendulum is given by T=2πlg+kxT = 2\pi\sqrt{\frac{l}{g}} + kxT=2πgl+kx, where lll is the length, ggg is acceleration due to gravity, and xxx is displacement. The dimensions of kkk are:
[L⁻¹T]
[LT⁻¹]
[L⁻¹T⁻¹]
[L⁻²T²]
Related Questions
Unit of stress is
N/m
N-m
N/m2N/{m^2}N/m2
N−m2N - {m^2}N−m2
The SI unit of length is the metre. Suppose we adopt a new unit of length which equal x metre. The area of 1m21{m^2}1m2 expressed in terms of the new unit has a magnitude
1/x
1/x²
x
x²
SI unit of intensity of wave is
Jm−2s−1{\rm{J}}{{\rm{m}}^{ - 2}}{{\rm{s}}^{ - 1}}Jm−2s−1
Jm−1s−2{\rm{J}}{{\rm{m}}^{ - 1}}{{\rm{s}}^{ - 2}}Jm−1s−2
Wm−2{\rm{W}}{{\rm{m}}^{ - 2}}Wm−2
Jm−2{\rm{J}}{{\rm{m}}^{ - 2}}Jm−2
