The time period of a simple pendulum is given by T=2πlg+kxT = 2\pi\sqrt{\frac{l}{g}} + kxT=2πgl+kx, where lll is the length, ggg is acceleration due to gravity, and xxx is displacement. The dimensions of kkk are:
[L⁻¹T]
[LT⁻¹]
[L⁻¹T⁻¹]
[L⁻²T²]
Related Questions
The damping force of an oscillating particle is observed to be proportional to velocity. The constant of proportionality can be measured in
Kg s−1{s^{ - 1}}s−1
Kg S
Kg ms−1{\rm{m}}{{\rm{s}}^{ - 1}}ms−1
Kg m−1s−1{{\rm{m}}^{ - 1}}{{\rm{s}}^{ - 1}}m−1s−1
