The time period of a simple pendulum is given by T=2πlg+kxT = 2\pi\sqrt{\frac{l}{g}} + kxT=2πgl+kx, where lll is the length, ggg is acceleration due to gravity, and xxx is displacement. The dimensions of kkk are:
[L⁻¹T]
[LT⁻¹]
[L⁻¹T⁻¹]
[L⁻²T²]
Related Questions
The SI unit of universal gas constant (R) is
Watt K−1mol−1Watt\;{K^{ - 1}}mo{l^{ - 1}}WattK−1mol−1
Newton K−1mol−1Newton\;{K^{ - 1}}mo{l^{ - 1}}NewtonK−1mol−1
Joule K−1mol−1Joule\;{K^{ - 1}}mo{l^{ - 1}}JouleK−1mol−1
Erg K−1mol−1Erg\;{K^{ - 1}}mo{l^{ - 1}}ErgK−1mol−1
The physical quantity which is not a unit of energy is
Volt-coulomb
MeV-sec
Henry(ampere)2Henry{(ampere)^2}Henry(ampere)2
Farad−(volt)2Farad - {(volt)^2}Farad−(volt)2
Which relation is wrong
λ = h/p
E = mc^2
E = 1/2mv
E = hv
