A student performs an experiment and obtains a value of $g = 9.7542 m/s^2$. The standard value is $g = 9.8 m/s^2$. Which of the following represents the student's result with the correct number of significant figures, considering the precision of the standard value?

In the determination of Young’s modulus $\left( {Y = \frac{{4\;MLg}}{{\pi \;\ell {d^2}}}} \right)$ by using Searle’s method, a wire of length L=2m and diameter d=0.5mm is used. For a load M=2.5 kg, an extension $\ell = 0.25mm$ in the length of the wire is observed. Quantities d and $\ell$ are measured using a screw gauge and a micrometer, respectively. They have the same pitch of 0.5 mm. The number of divisions on their circular scale is 100. The contributions to the maximum probable scale is 100. The contributions to the maximum probable error of the Y measurement

Which of the following has four significant figures?

The error in the measurement of the length of a simple pendulum is 0.2 % and the error in the time period is 1%. What is the maximum percentage error in the measurement of physical quantity having the dimensional formula $\left[ {L{T^{ - 2}}} \right]$

A rectangular piece of fabric measures 55.3 cm in length and 25 cm in width. Calculate the area of the fabric, expressing your answer to the correct number of significant figures.

The error in the measurement of the length of a simple pendulum is 0.2 % and the error in the time period is 1%. What is the maximum percentage error in the measurement of physical quantity having the dimensional formula $\left[ {L{T^{ - 2}}} \right]$

Given, potential difference $V = \left( {8 \pm 0.5} \right)$ volt and current $I = \left( {2 \pm 0.2} \right)$. The value of resistance R is

The length $l,$, breadth b and thickness t of a block are measured with the help of a metre scale. Given $l = 15.12 \pm 0.01$ cm, $b = 10.15 \pm 0.01$ cm, $t = 5.28 \pm 0.01$cm.The percentage error in volume is

In an experiment, the following observation’s were recorded: $L = 2.820\;m$, M=3.00 kg,l=0.087 cm, diameter D=0.041 cm. Taking g=9.81 $m/{s^2}$ using the formula,

$Y = \frac{{4MgL}}{{\pi {D^2}l}}$, the maximum permissible error in Y is

The period of oscillation of a simple pendulum is given by $T = 2\pi \sqrt {\frac{l}{g}}$ where l is about 100 cm and is known to have 1mm accuracy. The period is about 2s. The time of 100 oscillations is measured by a stop watch of least count 0.1 s . The percentage error in g is

Error in the measurement of radius of sphere is 2%. The error in the measurement of volume is