NEET Physics MCQs

The wavelength $\lambda$ of matter waves is given by $\lambda = \frac{h}{p}$, where $h$ is Planck's constant and $p$ is momentum. If a new quantity $Z$ is defined as $Z = \frac{h^2}{\lambda^2 p c}$, where $c$ is the speed of light, the dimensions of $Z$ are:

An electron is accelerated from rest through a potential difference of $V$ volts. If the de Broglie wavelength of the electron is $1.227 imes 10^{-2}$ nm, the potential difference is:

A proton is accelerated from rest through a potential difference $V$. If its de Broglie wavelength is $1.227 imes 10^{-3}$ nm, what is the potential difference $V$?

An alpha particle (charge $2e$ and mass $4m_p$, where $m_p$ is the proton mass) is accelerated through a potential difference of $V$ volts. If its de Broglie wavelength is $0.6135 imes 10^{-3}$ nm, what is $V$?

What is the de Broglie wavelength of an electron accelerated through a potential difference of 20000 V?

If the de Broglie wavelength of a neutron (mass $= 1.675 imes 10^{-27}$ kg) is $2 imes 10^{-14}$ m, through what potential difference has it been accelerated?

An electron is accelerated through a potential difference of 20,000 V. Its de Broglie wavelength is, (nearly): ($m_e = 9 imes 10^{-31} kg$)

A proton is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, (nearly): ($m_p = 1.67 imes 10^{-27} kg$)

An alpha particle is accelerated through a potential difference of 5,000 V. Its de Broglie wavelength is, (nearly): ($m_{\alpha} = 4m_p = 6.68 imes 10^{-27} kg$)

An electron is accelerated through a potential difference $V$. If its de Broglie wavelength is $0.123 Å$, the potential difference $V$ is approximately: