NEET Questions

Two capillary tubes of radii 0.2 mm and 0.4 mm are dipped vertically in water. The difference in the heights of the water level in the two tubes is $h_1$. If the two tubes are dipped in a liquid of surface tension $\frac{2}{3}$ that of water and density twice that of water, the difference in height of the liquid in the two tubes is $h_2$. The ratio $\frac{h_1}{h_2}$ is:

A capillary tube of radius 'r' is immersed in water and water rises in it to a height 'h'. The mass of the water in the capillary is 5g. Another capillary tube of radius '2r' is immersed in water. The mass of water that will rise in this tube is:

Water rises to a height of 10 cm in a capillary tube and mercury falls to a depth of 3.5 cm in the same tube. If the density of mercury is 13.6 g/cc and the angle of contact is 135°, the ratio of surface tension of water and mercury is:

If a capillary tube is tilted to an angle of 30° with the vertical, the rise of liquid in the tube will be:

Two capillary tubes of same diameter are dipped in two liquids A and B having densities $\rho_A$ and $\rho_B$ ($\rho_A > \rho_B$) and surface tensions $T_A$ and $T_B$ ($T_A < T_B$) respectively. If the angles of contact are same, then:

The height to which a liquid rises in a capillary tube is inversely proportional to:

If the contact angle between a liquid and glass is $0^\circ$, the liquid will:

A capillary tube of radius 'r' is dipped vertically in a liquid of density 'ρ' and surface tension 'T'. The angle of contact is zero. The height 'h' to which the liquid rises in the tube is given by:

Two capillary tubes of radii 0.5 mm and 1 mm are dipped in the same liquid. The ratio of the rise of liquid in the narrow tube to that in the wider tube is:

The capillary rise of a liquid in a tube depends upon: