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    9.

    The potential energy of a particle (Ux{U_x}) executing SHM is given by

    A

    Ux=k2(xβˆ’a)2{U_x} = \frac{k}{2}{\left( {x - a} \right)^2}

    B

    Ux=k1x+k2x2+k3x3{U_x} = {k_1}x + {k_2}{x^2} + {k_3}{x^3}

    C

    Ux=Aeβˆ’bx{U_x} = A{e^{ - bx}}

    D

    Ux=aconstant{U_x} = {\rm{a constant}}

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