A mutation changes a codon from UCG to UAG. This mutation is a:

The human genome contains approximately $3 imes 10^9$ base pairs per haploid set. If the distance between two consecutive base pairs is $0.34$ nm, calculate the approximate length of DNA in a diploid human cell.

If the distance between two consecutive base pairs is $0.34$ nm and the total number of base pairs of a DNA double helix in a typical mammalian cell is $6.6 imes 10^9$ bp, then the length of the DNA is approximately:

If the length of DNA in a mammalian cell is about 2.2 meters and there are $6.6 imes 10^9$ base pairs, what is the approximate distance between two consecutive base pairs?

If the distance between two consecutive base pairs is ${\rm{0}}{\rm{.34}}\,{\rm{nm}}$ and the total number of base pairs of a DNA double helix in a typical mammalian cell is $\;6.6\,\, imes \,\,{10^9}\,bp$ then the length of the DNA is approximately

If the total number of base pairs in a human DNA is $6.6 imes 10^9$ bp and each base pair extends for $0.34$ nm, what would be the approximate length of the DNA if it were stretched out?

If the distance between two consecutive base pairs is ${\rm{0}}{\rm{.34}}\,{\rm{nm}}$ and the total number of base pairs of a DNA double helix in a typical mammalian cell is $\;6.6\,\, imes \,\,{10^9}\,bp$ then the length of the DNA is approximately

A single human cell contains approximately $6.6 imes 10^9$ base pairs of DNA. Given that the distance between consecutive base pairs is $0.34$ nm, calculate the total length of DNA in a human cell.

A bacterial chromosome has $4.6 imes 10^6$ base pairs. Calculate the approximate length of this chromosome in micrometers, given that the distance between base pairs is 0.34 nm.