Two vectors $\vec{A}$ and $\vec{B}$ have magnitudes A and B respectively. If the magnitude of their cross product is $\frac{AB}{\sqrt{2}}$, which of the following could be the angle between $\vec{A}$ and $\vec{B}$?

The vector product of two vectors $\vec{A}$ and $\vec{B}$ has a magnitude of $AB$. What is the angle between them?

If $\overrightarrow F = \widehat i + 2\widehat j - 3\widehat k$ and $\overrightarrow r = 2\widehat i - \widehat j + \widehat k$. Find $\overrightarrow r imes \overrightarrow F$

The cross product $\vec{A} imes \vec{B}$ is anti-commutative. This means:

Which of the following is the correct representation of the cross product of two vectors $\vec{A}$ and $\vec{B}$?

The cross product $\hat{i} imes \hat{j}$ is equal to:

If $\vec{A} = 2\hat{i}$ and $\vec{B} = 3\hat{j}$, what is $\vec{A} imes \vec{B}$?

The angle between ${\rm{\vec A}}\;\,and\,{\rm{\vec B}}\,is\,heta$, the value of the triple product ${\rm{\vec A}}{\rm{.\vec B}} imes {\rm{\vec A}}$ is

Which of the following is true about the direction of the cross product $\vec{A} imes \vec{B}$?

The angle between ${\rm{\vec A}}\;\,and\,{\rm{\vec B}}\,is\,heta$, the value of the triple product ${\rm{\vec A}}{\rm{.\vec B}} imes {\rm{\vec A}}$ is

If $\overrightarrow F = 2\widehat i - 3\widehat j\,\,N$ and $\overrightarrow r = 3\widehat i + 2\widehat j\,\,m$ then torque $\overrightarrow au$ is