20 mL of a solution containing a mixture of $NaOH$ and $Na_2CO_3$ requires 10 mL of 0.5 N HCl for neutralization using phenolphthalein as an indicator. A further addition of 5 mL of the same HCl is required to reach the methyl orange endpoint. Calculate the equivalent weight of the mixture.

In the reaction, ${{\rm{N}}_2} o {\rm{N}}{{\rm{H}}_3}{\rm{.}}$. The eq.wt. of ${{\rm{N}}_2}$ and ${\rm{N}}{{\rm{H}}_3}$ are respectively equal to :

A metal M forms two oxides, M₂O₃ and MO₂. If 0.5 moles of M₂O₃ and 0.5 moles of MO₂ require 60 mL and 120 mL of 1 N HCl respectively for complete neutralisation, what is the equivalent weight of the metal M?

Which has maximum number of atoms ?

Cerric ammonium sulphate and potassium permanganate are used as oxidising agents in acidic medium for oxidation of ferrous ammonium sulphate to ferric sulphate. The ratio of number of moles of cerric ammonium sulphate required per mole of ferrous ammonium sulphate to the number of moles of ${\rm{KMn}}{{\rm{O}}_4}$ required per mole of ferrous ammonium sulphate, is

Milliequivalent of a solute in a solution can be given by:

The number of equivalent per mole of ${{\rm{H}}_2}{\rm{S}}$ used in its oxidation to ${\rm{S}}{{\rm{O}}_2}$ is :

A mixture of $NaHCO_3$ and $Na_2CO_3$ is titrated against $0.5$ N $HCl$ using phenolphthalein as the indicator. $10$ mL of the mixture consumes $4$ mL of $HCl$ to reach the endpoint. Methyl orange is then added to the same solution, and a further $6$ mL of $HCl$ is required to reach the second endpoint. What is the equivalent weight of the mixture?

In the reaction, ${\rm{C}}{{\rm{r}}_2}{\rm{O}}_7^{2 - } + 14{{\rm{H}}^ + } + 6{{\rm{I}}^ - } o 2{\rm{C}}{{\rm{r}}^{3 + }} + 3{{\rm{H}}_2}{\rm{O}} + 3{{\rm{I}}_2}$, The eq.wt. of ${\rm{C}}{{\rm{r}}^{3 + }}$) is :

Cerric ammonium sulphate and potassium permanganate are used as oxidising agents in acidic medium for oxidation of ferrous ammonium sulphate to ferric sulphate. The ratio of number of moles of cerric ammonium sulphate required per mole of ferrous ammonium sulphate to the number of moles of ${\rm{KMn}}{{\rm{O}}_4}$ required per mole of ferrous ammonium sulphate, is

When ${\rm{BrO}}_3^ -$ ion reacts with ${\rm{B}}{{\rm{r}}^ - }$ ion in acidic solution ${\rm{B}}{{\rm{r}}_2}$ is liberated. The equivalent weight of ${\rm{KBr}}{{\rm{O}}_3}$ is :