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For a reaction A + B β C, the rate law is found to be Rate = k[A]Β²[B]β»ΒΉ. If the concentration of A is tripled while keeping the concentration of B constant, the factor by which the reaction rate changes is:
3
1/3
1/9
9
The half-life of a first-order reaction is 20 minutes. What fraction of the reactant remains after 80 minutes?
1/2
1/4
1/8
1/16
A reaction between gases X and Y follows the rate law: Rate = k[X]Β²[Y]. If the concentration of X is tripled and the concentration of Y is halved, the new rate will be:
1.5 times the original rate
4.5 times the original rate
9 times the original rate
0.75 times the original rate
For a reaction with an activation energy () of 50 kJ/mol, how much would a 10Β°C increase in temperature increase the rate constant, according to the Arrhenius equation (assuming ) at room temperature (approx. 300K)?
Approximately half
Approximately double
Approximately quadruple
Negligible change
The hydrolysis of tert-butyl bromide in an aqueous medium follows the mechanism. If the concentration of tert-butyl bromide is doubled, and the concentration of water is tripled, how will the rate of the reaction be affected?
Doubles
Triples
Increases six-fold
Remains unchanged
A reaction follows the rate law: Rate = . If the concentrations of both A and B are halved, the rate of the reaction will become:
1/2 times the original rate
1/4 times the original rate
1/(4β2) times the original rate
1/8 times the original rate
A reaction has a rate constant 'k' at temperature 'T'. If the temperature is increased by 10Β°C, the rate constant becomes '2k'. What is the activation energy () for the reaction (R = 8.314 J/mol K)?
Approximately 12 kJ/mol
Approximately 25 kJ/mol
Approximately 58 kJ/mol
Approximately 116 kJ/mol
A radioactive sample has a half-life of 10 days. What fraction of the original sample will remain after 20 days?
1/2
1/4
1/8
1/16