1.

    Among the following statement, the correct statement about PH3{\rm{P}}{{\rm{H}}_3} and NH3{\rm{N}}{{\rm{H}}_3} is:

    A

    NH3{\rm{N}}{{\rm{H}}_3} is a better electron donor because the lone pair of electron occupies spherical s-orbital and is less directional

    B

    PH3{\rm{P}}{{\rm{H}}_3} is a better electron donor because the lone pair of electron occupies sp3s{p^3}orbital and is more directional

    C

    NH3{\rm{N}}{{\rm{H}}_3} is a better electron donor because the lone pair of electron occupies sp3s{p^3}orbital and more directional

    D

    PH3{\rm{P}}{{\rm{H}}_3} is a better electron donor because the lone pair of electron occupies spherical s-orbital and is less directional

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    Related Questions

    1.

    Mixture used in Holme’s signals is

    A

    CaC2+NH3Ca{C_2} + N{H_3}

    B

    CaC2+PH3Ca{C_2} + P{H_3}

    C

    CaC2+Ca3P2Ca{C_2} + C{a_3}{P_2}

    D

    Ca3P2+PH3C{a_3}{P_2} + P{H_3}

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    4.

    Holme’s signals can be obtained by using

    A

    CaC2+CaCN2Ca{C_2} + CaC{N_2}

    B

    CaC2+Ca3P2Ca{C_2} + C{a_3}{P_2}

    C

    CaC2+CaCO3Ca{C_2} + CaC{O_3}

    D

    Ca3P2+CaCN2C{a_3}{P_2} + CaC{N_2}

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    7.

    The reaction of PCl3PCl_3 with water produces:

    A

    H3PO4H_3PO_4 and HClHCl

    B

    H3PO3H_3PO_3 and HClHCl

    C

    H4P2O7H_4P_2O_7 and HClHCl

    D

    H3PO2H_3PO_2 and HClHCl

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