Related Questions

    6.

    Which one of the following will show optical isomerism?

    A

    HOβˆ’C∣∣HHβˆ’CO2H{\rm{HO}} - \mathop {\mathop {\rm{C}}\limits_|^| }\limits_{\rm{H}}^{\rm{H}} - {\rm{C}}{{\rm{O}}_2}{\rm{H}}

    B

    H3Cβˆ’C∣∣OHHβˆ’CO2H{{\rm{H}}_3}{\rm{C}} - \mathop {\mathop {\rm{C}}\limits_|^| }\limits_{OH}^{\rm{H}} - {\rm{C}}{{\rm{O}}_2}{\rm{H}}

    C

    H3Cβˆ’C∣∣HCH3βˆ’CO2H{{\rm{H}}_3}{\rm{C}} - \mathop {\mathop {\rm{C}}\limits_|^| }\limits_H^{{\rm{C}}{{\rm{H}}_3}} - {\rm{C}}{{\rm{O}}_2}{\rm{H}}

    D

    H3Cβˆ’C∣∣ClCH3βˆ’CO2H{{\rm{H}}_3}{\rm{C}} - \mathop {\mathop {\rm{C}}\limits_|^| }\limits_{Cl}^{{\rm{C}}{{\rm{H}}_3}} - {\rm{C}}{{\rm{O}}_2}{\rm{H}}

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    10.

    One of the following compounds exhibit geometrical iosmerism

    A

    CH3CH2CH2CH3{\rm{C}}{{\rm{H}}_3}{\rm{C}}{{\rm{H}}_2}{\rm{C}}{{\rm{H}}_2}{\rm{C}}{{\rm{H}}_3}

    B

    CH3βˆ’HC(CH3)βˆ’H(C)CH3βˆ’CH3{\rm{C}}{{\rm{H}}_3} - {\rm{HC}}\left( {{\rm{C}}{{\rm{H}}_3}} \right) - {\rm{H}}\left( {\rm{C}} \right){\rm{C}}{{\rm{H}}_3} - {\rm{C}}{{\rm{H}}_3}

    C

    CH3βˆ’HC(CH3)βˆ’CH3{\rm{C}}{{\rm{H}}_3} - {\rm{HC}}\left( {{\rm{C}}{{\rm{H}}_3}} \right) - {\rm{C}}{{\rm{H}}_3}

    D

    CH3CH=CHβˆ’CH3{\rm{C}}{{\rm{H}}_3}{\rm{CH}} = {\rm{CH}} - {\rm{C}}{{\rm{H}}_3}

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