NEET Physics Alternating Current A.C Across R-L, R-C, L-C And L-C-R Circuit MCQs

A series R-L-C circuit with $R = 10 \Omega$, $L = 0.1 H$, and $C = 10 \mu F$ is connected to an AC source with $V_{rms} = 200 V$ and variable frequency. At resonance, the average power dissipated in the circuit is:

In a series R-C circuit, the voltage across the capacitor lags the current by $\frac{\pi}{2}$. If the frequency of the source is doubled, the phase difference between the voltage across the capacitor and the current will:

A series L-C-R circuit is connected to an AC source. At resonance, which of the following quantities is minimum?

In a series R-L circuit, the voltage across the inductor leads the current by $\frac{\pi}{2}$. If a capacitor is added in series such that the circuit resonates, the phase difference between the source voltage and the current will be:

A series RLC circuit has $R = 20\Omega$, $L = 20 mH$, and $C = 0.5 \mu F$. It is connected to a variable frequency AC source with a fixed rms voltage. The frequency at which the current is half its maximum value is $f_1$. If the capacitance is doubled, the corresponding frequency is $f_2$. Find the ratio $\frac{f_1}{f_2}$.

A series R-L-C circuit with $R = 5 \Omega$, $L = 20 mH$, and $C = 5 \mu F$ is driven by a sinusoidal voltage source $V(t) = 100 \sin(500t)$ volts. What is the average power dissipated in the circuit?

A series R-L circuit is connected to an AC source. If the inductance is doubled while keeping the resistance and frequency constant, the impedance of the circuit will:

In a series R-C circuit connected to an AC source, the current leads the voltage by an angle $\phi$. If the capacitance is halved while keeping the resistance and frequency constant, the phase angle $\phi$ will:

At resonance in a series L-C-R circuit, the impedance is:

In an L-C-R series circuit, the current will lag the voltage when: