An AC voltage source with $V_{rms} = 100V$ is connected to a purely resistive load. If the peak instantaneous power delivered to the load is 200W, what is the average power delivered?

A non-ideal inductor with inductance L and internal resistance r is connected to an AC source with voltage $v(t) = V_m\sin(\omega t)$. If the instantaneous current through the inductor is $i(t) = I_m\sin(\omega t - \phi)$, which of the following expressions CORRECTLY represents the average power dissipated in the inductor?

If ${E_0}$ is the peak emf, ${I_0}$ is the peak current and $\phi$ is the phase difference between them, then the average power dissipation in the circuit is

An inductor of reactance $1\,\Omega$ and resistor of $2\Omega$ are connected in series. To the terminals of a 6v (rms) a.c. source. The power dissipated in the circuit is