The Question is from neet-physics electromagnetic-waves electromagnetic-spectrum, and it was created by the author ABDUL JILANI BASHA

Question

A monochromatic electromagnetic wave propagates in vacuum. If its electric field amplitude is $E_0$ and magnetic field amplitude is $B_0$, which of the following relations is NOT correct?

ABDUL JILANI BASHA · Accepted Answer

## CORE INFORMATION
✓ **Answer**: C
## CONCEPT FRAMEWORK
	**Primary Concept**: Electromagnetic Waves
	**Related Topics**: Electric and Magnetic Fields, Energy Density, Speed of Light
	**Prerequisites**: Understanding of electromagnetic wave properties, relationship between electric and magnetic fields in EM waves, energy density of electric and magnetic fields.
## SOLUTION PATHWAY
**Given Information**:
	* A monochromatic electromagnetic wave propagates in vacuum.
	* Electric field amplitude is E₀.
	* Magnetic field amplitude is B₀.

**Method & Steps**:
	1.	Analyze the relationship between electric and magnetic field amplitudes in an electromagnetic wave.
		Reasoning: In an electromagnetic wave, the electric and magnetic field amplitudes are related by the speed of light in vacuum.
		Formula/Rule: E₀ = cB₀
	2.	Evaluate the energy density distribution in electromagnetic waves.
		Reasoning: The energy density of an electromagnetic wave is equally distributed between the electric and magnetic fields.
		Formula/Rule: Energy density (electric) = 1/2 * ε₀ * E² and Energy density (magnetic) = 1/2 * (B²/μ₀) and they are equal
	3.	Examine the direction of electric and magnetic fields and the propagation direction.
		Reasoning: The electric field, magnetic field, and propagation direction are mutually perpendicular in an electromagnetic wave.
	4.	Identify the incorrect relationship.
		Result: The relation E₀B₀ = c is incorrect. The correct relation is E₀ = cB₀

## OPTION ANALYSIS
[A] ✓: E₀ = cB₀ is a correct relationship between the electric and magnetic field amplitudes in an electromagnetic wave.
[B] :x: The energy density is equally distributed between electric and magnetic fields is a correct property of electromagnetic waves.
[C] :x: E₀B₀ = c is incorrect. The correct relationship is E₀ = cB₀ or E₀/B₀ = c.
[D] :x: The directions of E, B, and propagation are mutually perpendicular is a fundamental property of electromagnetic waves. 
 ## LEARNING AIDS
	**Common Mistakes**:
		1.[Error 1]: Confusing the relationship between E₀ and B₀. The correct relation is E₀ = cB₀, not E₀B₀ = c.
			How to avoid: Remember the relationship derives from the speed of light connecting the fields.
		2.[Error 2]: Assuming energy density is not equally distributed. Energy densities of electric and magnetic fields are equal in electromagnetic waves.
			How to avoid: Recall that both contribute equally to the wave's energy.
	**Quick Tips**:
		1.[Helpful shortcut]: Remember the speed of light 'c' acts as a conversion factor between the electric and magnetic field amplitudes in vacuum.
		2.[Memory aid]: Think of the electromagnetic wave as a traveling disturbance where the electric and magnetic fields are perpendicular to each other and both are perpendicular to the direction of travel.

ABDUL JILANI BASHA · Answer

E₀ = cB₀

ABDUL JILANI BASHA · Answer

The energy density is equally distributed between electric and magnetic fields

ABDUL JILANI BASHA · Answer

The correct Option is "E₀B₀ = c"

ABDUL JILANI BASHA · Answer

The directions of E, B and propagation are mutually perpendicular

NEET Physics Electromagnetic Waves Electromagnetic Spectrum MCQs

Select Topic

Question Tags

Question Tags

Question Tags

Question Tags

Question Tags

Question Tags

Question Tags

Question Tags

Question Tags

Question Tags

NEET Subjects

Our Bots

Company