A proton and an electron are released from rest in a uniform electric field. Which particle will experience a greater magnitude of acceleration?

When a negative charge is taken at a height from earth’s surface, then its potential energy

A charged particle of mass $5 imes {10^{ - 5}}kg$ is held stationary in space by placing it in an electric field of strength ${10^7}N{C^{ - 1}}$ directed vertically downwards. The charge on the particle is

A negatively charged dust particle of mass $m$ and charge $-q$ falls from rest through a vertical distance $h$ in a uniform electric field $E$ directed upwards. What is the time taken for the dust particle to fall this distance?

A hollow conducting spherical shell of radius $R$ is charged with $Q$ coulomb. The amount of work done for moving any charge $q$ from the centre to the surface of the shell will be

There is 10 units of charge at the centre of a circle of radius $10m.$ The work done in moving 1 unit of charge around the circle once is

An electron initially at rest falls a distance of 1.5 cm in a uniform electric field of magnitude 2$imes {10^4}$ N/C. The time taken by electron to fall this distance is

A charged water drop whose radius is $0.1\;\mu m$ is in equilibrium in an electric field. If charge on it is equal to charge of an electron, then intensity of electric field will be $\left( {g = 10m{s^{ - 1}}} \right)$

The magnitude of electric field intensity $E$ is such that, an electron placed in it would experience an electrical force equal to its weight is given by

There is a uniform electric field of strength ${10^3}V/m$ along $y$-axis. A body of mass $1g$ and charge ${10^{ - 6}}C$ is projected into the field from origin along the positive $x$-axis with a velocity $10m/s.$ Its speed in $m/s$ after $10s$ is (Neglect gravitation)

The electric field lines due to a positive point charge are