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A large cylindrical tank filled with water to a height has a small hole at a depth below the water surface. If the hole is enlarged such that its area doubles, how does the range of the water stream exiting the hole change? (Assume ideal fluid behavior and no air resistance)
The range doubles.
The range increases by a factor of sqrt(2).
The range decreases by a factor of 2.
The range remains the same.
A container filled with an ideal fluid has two small holes of equal area, one at depth and the other at depth . If the velocity of efflux through the hole at depth is , what is the horizontal distance between the points where the two streams hit the ground? (Assume the holes are close to the base of the container, and the base is at a height above the ground)
sqrt(hH)
2sqrt(hH)
4sqrt(hH)
sqrt(2hH)
A tank filled with water to a height has a small hole in its side at a depth from the water surface. The range of the emerging stream is . Now, the tank is placed on a smooth horizontal surface and given a constant horizontal acceleration . The new range of the stream will be:
R
R(1+a/g)
R\sqrt{1+a^2/g^2}
R(1+a/\sqrt{2gH})
If the speed of efflux from an orifice is 'v', what is the horizontal range of the liquid stream assuming it emerges horizontally at a height 'H' above the ground?
v * sqrt(H/g)
2v * sqrt(H/g)
v * sqrt(2H/g)
v * sqrt(g/2H)