NEET Physics Mechanical Properties Of Fluids MCQs

A tank filled with water has a small hole at a depth 'd' below the surface. The velocity of efflux is 'v'. If the water is replaced with a liquid of density twice that of water, the new velocity of efflux will be:

A large open tank is filled with water to a height 'H'. A small hole is made at a depth 'h' below the water surface. If 'R' is the range of the efflux, the maximum range is achieved when:

According to Torricelli's theorem, the velocity of efflux from a small hole in a tank is independent of:

A thin rectangular plate of dimensions $5 \, cm imes 2 \, cm$ is suspended vertically with its long side horizontal, with half of it immersed in a liquid of surface tension $0.04 \, N/m$. The apparent weight of the plate in the liquid is $0.01 \, N$ less than its weight in air. The contact angle between the liquid and the plate is (Assume $g = 10 \, m/s^2$):

Two soap bubbles of radii $r_1$ and $r_2$ coalesce under isothermal conditions to form a bigger bubble of radius $R$. If the atmospheric pressure is $P_0$, the surface tension of the soap solution is:

A capillary tube of radius $r$ is immersed vertically in a liquid of density $\rho$ and surface tension $T$. The angle of contact is $heta$. The height $h$ to which the liquid rises in the tube is given by:

A small air bubble of radius $r$ rises steadily through a liquid of density $\rho$ at a terminal velocity $v$. If the coefficient of viscosity of the liquid is $\eta$, the surface tension of the liquid is (neglecting the density of air):

A liquid rises to a height 'h' in a capillary tube of radius 'r'. If the radius of the capillary tube is doubled, the height to which the liquid rises in the tube will be:

Two spherical bubbles of radii $r_1$ and $r_2$ in air combine to form a bigger bubble. The radius of the bigger bubble is:

According to Poiseuille's equation, the rate of flow of a liquid through a narrow tube is directly proportional to which power of the radius of the tube?