NEET Physics Mechanical Properties Of Fluids MCQs

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    NEET Questions / Physics / Mechanical Properties Of Fluids

    77.

    A soap bubble of radius R1R_1 is placed on another soap bubble of radius R2R_2 (R2>R1R_2 > R_1). The radius of curvature of the common surface is RR. If Οƒ\sigma is the surface tension of the soap solution, the expression for RR considering excess pressure is:

    A

    R=R1R2R2βˆ’R1R = \frac{R_1 R_2}{R_2 - R_1}

    B

    R=R1R2R2+R1R = \frac{R_1 R_2}{R_2 + R_1}

    C

    R=R1+R2R1R2R = \frac{R_1 + R_2}{R_1 R_2}

    D

    R=R2βˆ’R1R1R2R = \frac{R_2 - R_1}{R_1 R_2}

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    78.

    A spherical liquid drop of radius 'r' is divided into 'n' identical droplets. If surface tension is 'T', the work done in this process is:

    A

    4Ο€r2T(n1/3βˆ’1)4\pi r^2 T(n^{1/3} - 1)

    B

    4Ο€r2T(n2/3βˆ’1)4\pi r^2 T(n^{2/3} - 1)

    C

    4Ο€r2T(nβˆ’1)4\pi r^2 T(n - 1)

    D

    4Ο€r2T(n1/2βˆ’1)4\pi r^2 T(n^{1/2} - 1)

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