A particle is projected vertically upwards with an initial speed 'u'. At a height 'h' above the ground, its speed is 'v'. What is the maximum height reached by the particle?

The velocities of a body executing $SHM$ are $3\,cm/s$ and $4\,cm/s$. When the displacements are $4\,cm$ and $3\,cm$ respectively then period is

The displacement of a particle executing SHM is given by $y = 0.25{\rm{ }}sin{\rm{ }}200t{\rm{ }}\,\,\,cm$ the maximum speed of the particle is

This time period of a particle undergoing SHM is 16 s. It starts motion from the mean position. After 2 s, its velocity is $0.4{\rm{m}}{{\rm{s}}^{ - 1}}$ The amplitude is

A body describes $SHM$ with an amplitude of $50\,cm$ and a time period of 1.57 seconds. The velocity of the body when its displacement becomes $30\,cm$ is

A simple pendulum performs simple harmonic motion about $\;X = 0$ with an amplitude A and time period $T$. The speed of the pendulum at $X = \frac{A}{2}$ will be

The displacement of a particle executing SHM is given by $y = 0.25{\rm{ }}sin{\rm{ }}200t{\rm{ }}\,\,\,cm$ the maximum speed of the particle is

A S.H.M. has amplitude $'a'$ and time period $T$.The maximum velocity will be

The displacement x(in metre) of a particle in simple harmonic motion is related to time t(in second) as $x = 0.01\cos \left( {\pi t + \frac{\pi }{4}} \right)$ The frequency of the motion will be

This time period of a particle undergoing SHM is 16 s. It starts motion from the mean position. After 2 s, its velocity is $0.4{\rm{m}}{{\rm{s}}^{ - 1}}$ The amplitude is

The acceleration of a particle in SHM is $0.8\,\,m{s^{ - 2}}$ when its displacement is 0.2 m. The frequency of oscillation is