A particle is projected vertically upwards with an initial speed 'u'. At a height 'h' above the ground, its speed is 'v'. What is the maximum height reached by the particle?

A particle's position vector is described by $\vec r = 2\cos \omega t\hat x + 2\sin \omega t\hat y$, where $\omega$ is constant. What is the path of the particle?

A particle moves in x-y plane according to rule x=a sin⁡ωt and y=a cos⁡ωt. The particle follows

A particle executing S.H.M. of amplitude 4 $cm$ and $T$=4 s. The time taken by it to move from positive extreme position to half the amplitude is

A particle executes simple harmonic motion between $x$ $= - A\,\,{\rm{and}}\,\,x = + A$ The time taken for it to go from $0{\rm{ }}to\;A/2\,\,is\,\,{T_1}$ and to go from $A/2$ to $A\,\,{\rm{is}}\,\,{T_2}$ Then

Two equations of two S.H.M. are $y = a\sin \left( {\omega t - \alpha } \right)$ and $y = b\cos \left( {\omega t - \alpha } \right)$ The phase difference between the two is

A large horizontal surface moves up and down in SHM with an amplitude of 1 cm. if a mass of 10 kg (which is placed on the surface) is to remain continuously is in contact with it. The maximum frequency of SHM will be

Which one of the following statements is true for the speed v and the acceleration a of a particle executing simple harmonic motion

A particle executes S.H.M. with a period of 6 second and amplitude of 3 $cm$ . Its maximum speed in $cm$/$s$ is

A body moving with uniform velocity has:

Which of the following is the correct unit of acceleration?