A particle is projected vertically upwards with an initial speed 'u'. At a height 'h' above the ground, its speed is 'v'. What is the maximum height reached by the particle?
u²/2g
v²/2g
h
v²/2g + h
Related Questions
Which of the following is the correct unit of acceleration?
m/s
m/s²
m²/s
m²/s²
A particle moving along the xxx axis executes simple harmonic motion, then the force acting on it is given by
−AKx - A{\rm{ }}Kx−AKx
Acos(Kx)A\cos \left( {Kx} \right)Acos(Kx)
Aexp(−Kx)A\exp \left( { - Kx} \right)Aexp(−Kx)
AKxA{\rm{ }}KxAKx
