$(V_2 - V_1)(P_2 - P_1)$

$\frac{1}{2}(V_2 - V_1)(P_2 - P_1)$

$\frac{1}{2}(V_2 + V_1)(P_2 + P_1)$

$(V_2 + V_1)(P_2 + P_1)$

No work is done by or on the gas.

The internal energy of the gas remains constant.

The temperature of the gas remains constant.

The pressure of the gas remains constant.

$P\left( {{V_2} - {V_1}} \right)$

$P\left( {{V_1} - {V_2}} \right)$

$P\left( {V_1^\gamma - V_2^\gamma } \right)$

$P\frac{{{V_1}{V_2}}}{{{V_2} - {V_1}}}$

$P\left( {{V_2} - {V_1}} \right)$

$P\left( {{V_1} - {V_2}} \right)$

$P\left( {V_1^\gamma - V_2^\gamma } \right)$

$P\frac{{{V_1}{V_2}}}{{{V_2} - {V_1}}}$

Compressing the gas isothermally will require more work to be done.

Compressing the gas through adiabatic process will require more work to be done.

Compressing the gas isothermally or adiabatically will require the same amount of work.

Which of the case (whether compression through isothermal or through adiabatic process) requires more work will depend upon the atomicity of the gas.

$8.31 imes {10^3}J$

$8.31 imes {10^{ - 3}}J$

$8.31 imes {10^{ - 2}}J$

$8.31 imes {10^2}J$

Compressing the gas isothermally will require more work to be done.

Compressing the gas through adiabatic process will require more work to be done.

Compressing the gas isothermally or adiabatically will require the same amount of work.

Which of the case (whether compression through isothermal or through adiabatic process) requires more work will depend upon the atomicity of the gas.

$1 - \frac{1}{{\rm{\gamma }}}$

$1 + \frac{1}{{\rm{\gamma }}}$

$1 - \frac{2}{{\rm{\gamma }}}$

$1 + \frac{2}{{\rm{\gamma }}}$

$8.31 imes {10^3}J$

$8.31 imes {10^{ - 3}}J$

$8.31 imes {10^{ - 2}}J$

$8.31 imes {10^2}J$

The work is done by the gas

Internal energy of the gas increases

Both 1 and 2

None from 1 and 2

$W/2$

$3W/2$

$5W/2$

$W$