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    2.

    A calorie is a unit of heat and equal 4.2 J. Suppose we employ a system of units in which the unit of mass is α\alpha kg, the unit of length is β\beta metre and the unit of time is γ sec. In this new system. 1 calorie =

    A

    α1β2γ2{{\rm{\alpha }}^{ - 1}}{{\rm{\beta }}^{ - 2}}{{\rm{\gamma }}^2}

    B

    4.2αβ2γ24.2{\rm{\alpha }}{{\rm{\beta }}^2}{{\rm{\gamma }}^2}

    C

    αβ2γ2{\rm{\alpha }}{{\rm{\beta }}^2}{{\rm{\gamma }}^2}

    D

    4.2α1β2γ24.2{{\rm{\alpha }}^{ - 1}}{{\rm{\beta }}^{ - 2}}{{\rm{\gamma }}^2}

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    8.

    Length is measured in metre and time in second as usual. But a new unit of mass is so chosen that G=1. This new unit of mass is equal to

    A

    1.5imes107kg1.5 imes {10^7}kg

    B

    1.5imes1010kg1.5 imes {10^{10}}kg

    C

    6.67imes1011kg6.67 imes {10^{ - 11}}kg

    D

    6.67imes108kg6.67 imes {10^{ - 8}}\,kg

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