NEET Physics MCQs

A simple pendulum with a bob of mass $m$ and length $L$ is oscillating in a lift accelerating upwards with acceleration $a$. The effective acceleration due to gravity experienced by the pendulum is:

The angular velocity of the earth with which it has to rotate so that acceleration due to gravity on ${60^0}$ latitude becomes zero is (Radius of earth $= 6400\;km.$. At the poles $g = 10\;m{s^{ - 2}}$)

$R$ is the radius of the earth and $\omega$ is its angular velocity and ${g_p}$ is the value of $g$ at the poles. The effective value of $g$ at the latitude $\lambda = 60^\circ$ will be equal to

A body weights $49\,N$ on a spring balance at the North Pole. What will be its weight recorded on the same weighing machine, if it is shifted to the equator? (Use, $g = \frac{{GM}}{{{R^2}}} = 9.8\,\,m{s^{ - 2}}$ and radius of earth, $R = 6400\,\,km$)

The acceleration due to gravity on the earth’s surface at the poles is $g$ and angular velocity of the earth about the axis passing through the pole is $\omega .$ An object is weighed at the equator and at a height $h$ above the poles by using a spring balance. If the weights are found to be same, then $h$ is ($h < < R,$ where $R$ the radius of the earth)

A box weighs $196\,N$ on a spring balance at the north pole. Its weight recorded on the same balance, if it is shifted to the equator is close to (Take, $g = 10\,m{s^{ - 2}}$ at the north pole and the radius of the earth = 6400 km)

In order to make the effective acceleration due to gravity equal to zero at the equator, the angular velocity of rotation of the earth about its axis should be $\left( {g = 10\,m{s^{ - 2}}\,\,{ext{and radius of earth is 64000 km}}} \right)$

Assertion: The time period of a pendulum, on a satellite orbiting the earth is infinity.Reason: Time period of a pendulum is inversly proportional to $\sqrt{g}$

The imaginary angular velocity of the earth for which the effective acceleration due to gravity at the equator shall be zero is equal to(Take, $g=10 \mathrm{~ms}^{-2}$ for the acceleration due to gravity, if the earth were at rest, radius of earth equal to $6400 \mathrm{~km}$ and $\lambda=60$ )

$R$ is the radius of Earth and $\omega$ is its angular velocity and $g_p$ is the value of $g$ at the poles. The effective value of $g$ at a latitude $\lambda=60^{\circ}$.