NEET Physics MCQs

    Sharpen your Physics skills with chapter-wise NEET practice questions. Designed for NEET aspirants, these questions cover all Physics topics.

    NEET Questions / Physics

    22481.

    In a diffraction pattern due to a single slit of width ‘a’, the first minimum is observed at an angle 30o{30^{\rm{o}}} when light of wavelength 5000 Ao\mathop {\rm{A}}\limits^{\rm{o}} is incident on the slit. The first secondary maximum is observed at an angle of:

    A

    sin1(14){\sin ^{ - 1}}\,\left( {\frac{1}{4}} \right)

    B

    sin1(23){\sin ^{ - 1}}\,\left( {\frac{2}{3}} \right)

    C

    sin1(12){\sin ^{ - 1}}\,\left( {\frac{1}{2}} \right)

    D

    sin1(34){\sin ^{ - 1}}\,\left( {\frac{3}{4}} \right)

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    22482.

    Electrons of mass m with de-Broglie wavelength λ\lambda fall on the target in an X-ray tube. The cutoff wavelength (λ0)({\lambda _0}) of the emitted X-ray is:

    A

    λ0=λ{\lambda _0} = \lambda

    B

    λ0=2mcλ2h{\lambda _0} = \frac{{2mc{\lambda ^2}}}{h}

    C

    λ0=2hmc{\lambda _0} = \frac{{2h}}{{mc}}

    D

    λ0=2m2c2λ3h2{\lambda _0} = \frac{{2{m^2}{c^2}{\lambda ^3}}}{{{h^2}}}

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    22484.

    An electron of mass m and a photon have same energy E. the ratio of de-Brogile wavelengths associated with them is:

    SS

    (c being velocity of light)

    A

    1c(E2m)12\frac{{\rm{1}}}{{\rm{c}}}{\left( {\frac{{\rm{E}}}{{{\rm{2m}}}}} \right)^{\frac{1}{2}}}

    B

    (E2m)12{\left( {\frac{{\rm{E}}}{{{\rm{2m}}}}} \right)^{\frac{1}{2}}}\,

    C

    c(2mE)12{\rm{c(2mE}}{{\rm{)}}^{\frac{{\rm{1}}}{{\rm{2}}}}}

    D

    1c(2mE)12\,\frac{{\rm{1}}}{{\rm{c}}}{\left( {\frac{{{\rm{2m}}}}{{\rm{E}}}} \right)^{\frac{1}{2}}}

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    22489.

    Electrons of mass m with de-Broglie wavelength λ\lambda fall on the target in an X-ray tube. The cutoff wavelength (λ0)({\lambda _0}) of the emitted X-ray is:

    A

    λ0=λ{\lambda _0} = \lambda

    B

    λ0=2mcλ2h{\lambda _0} = \frac{{2mc{\lambda ^2}}}{h}

    C

    λ0=2hmc{\lambda _0} = \frac{{2h}}{{mc}}

    D

    λ0=2m2c2λ3h2{\lambda _0} = \frac{{2{m^2}{c^2}{\lambda ^3}}}{{{h^2}}}

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