A colloidal solution of gold nanoparticles is prepared by reduction of $HAuCl_4$. Which of the following methods is MOST EFFECTIVE for purifying this solution from excess reactants and small ionic byproducts?

What volume of 0.40 $M$ ${\rm{N}}{{\rm{a}}_2}{{\rm{S}}_2}{{\rm{O}}_3}$ would be required to react with the ${{\rm{I}}_2}$ liberated by adding excess of KI to 50 mL of 0.20 $M$ ${\rm{CuS}}{{\rm{O}}_4}$ solution?

1 gram of sodium hydroxide is neutralized with excess hydrochloric acid. If 0.73 g of sodium chloride is formed, what is the percentage yield of the reaction?

What is the normality of a ${\rm{KMn}}{{\rm{O}}_4}$ solution to be used as an oxidant in acid medium, which contain 15.8 g of the compound in 100 mL of solution? Mol. wt. of ${\rm{KMn}}{{\rm{O}}_4}$ is 158 :

Weight of ${\rm{FeS}}{{\rm{O}}_4}\left( {{\rm{mol}}{\rm{.wt}}{\rm{.}} = 152} \right)$ oxidized by 200 mL of 1 $N$ ${\rm{KMn}}{{\rm{O}}_4}$ solution is :

How many gram of ${{\rm{I}}_2}$ are present in a solution which requires 40 mL, of 0.11 N ${\rm{N}}{{\rm{a}}_2}{{\rm{S}}_2}{{\rm{O}}_3}$ to react with it, ${{\rm{S}}_2}{\rm{O}}_3^{2 - } + {{\rm{I}}_2} o {{\rm{S}}_4}{\rm{O}}_6^{2 - } + 2{{\rm{I}}^ - }?$

In the reaction, ${\rm{VO}} + {\rm{F}}{{\rm{e}}_2}{{\rm{O}}_3} o {\rm{FeO}} + {{\rm{V}}_2}{{\rm{O}}_5}{\rm{.}}$. The eq.wt. of ${{\rm{V}}_2}{{\rm{O}}_5}$ is equal to its :

How many g of ${\rm{KMn}}{{\rm{O}}_4}$ are needed to prepare 3.75 litre of 0.850 $N$ solution if ${\rm{KMn}}{{\rm{O}}_4}$ is reduced as, ${\rm{MnO}}_4^ - + 8{{\rm{H}}^ + } + 5{\rm{e}} o {\rm{M}}{{\rm{n}}^{2 + }} + 4{{\rm{H}}_2}{\rm{O}}$

100g of a liquid A (molar mass 140 g/mol) and 100g of liquid B (molar mass 70 g/mol) form an ideal solution. What is the mole fraction of B in the vapor phase? (Assume $P^0_A = 70$ mmHg and $P^0_B = 140$ mmHg)

What is the molality of a solution where the mole fraction of the solute is 0.02 and the solvent is water?

What mass of ${\rm{Mn}}{{\rm{O}}_2}$ is reduced by 35 mL of 0.16 $N$ oxalic acid in acidic solution? The skeleton equation is, ${\rm{Mn}}{{\rm{O}}_2} + {{\rm{H}}^ + } + {{\rm{H}}_2}{{\rm{C}}_2}{{\rm{O}}_4} o {\rm{C}}{{\rm{O}}_2} + {{\rm{H}}_2}{\rm{O}} + {\rm{M}}{{\rm{n}}^{2 + }}:$