Raising the temperature of a reversible chemical reaction :
Favours the forward rate only
Favours the backward rate only
Favours both the forward and backward rates as the case may be
Favours neither the forward nor backward rates
Related Questions
In the reaction the formation of will be favoured at
low and high
high and low
low and low
high and high
For the reaction,
the position of equilibrium can be shifted to the right by
Doubling the volume
Increasing the temperature
Addition of equimolar quantities of and
Addition of at constant volume
The law of mass action was enunciated by
Graham
Bodestein
Rutherford
Guldberg and Waage
The equilibrium constant of the following are, , , . The equilibrium constant (K) of the reaction will be
The reaction quotient for the reaction is given by: The reaction will proceed from right to left if:
Q < {K_c}
Q > {K_c}
In the above reaction, one mole of each of acetic acid and alcohol are heated in the presence of little conc. . On equilibrium being attained
1 mole of ethyl acetate is formed
2 mole of ethyl acetate is formed
mole of ethyl acetate is formed
mole of ethyl acetate is formed
In a flask, colourless is in equilibrium with brown coloured . At equilibrium, when the flask is heated at 100\,^\circ C the brown colour deepens and on cooling it becomes less coloured. The change in enthalpy for the system is :
Negative
Positive
Zero
Undefined
In the reaction , at equilibrium, adding more will:
Have no effect on the equilibrium position.
Shift the equilibrium to the left, decreasing the concentration of HI.
Shift the equilibrium to the right, increasing the concentration of HI.
Decrease the value of the equilibrium constant.
For the reaction, in a vessel, after the addition of equal number of mole of and , equilibrium state is formed. Which of the following is correct?