NEET Physics Electrostatic Charges and Fields MCQs

A charged particle of mass $m$ and charge $q$ enters a region of uniform electric field $E$ with a velocity $v$ perpendicular to the field. The time taken by the particle to traverse a distance $d$ along the field direction is:

A proton enters a uniform electric field $E$ with velocity $v$ parallel to the field. What will be the path followed by the proton?

A toy car with charge $q$ moves on a frictionless horizontal plane under a uniform electric field $\overrightarrow{E}$. Its velocity increases from 0 to $6 \, m/s$ in one second due to the force $q\overrightarrow{E}$. If the field's direction is reversed at that instant, and the car continues for two more seconds, what are its average velocity and average speed over the three seconds?

An electron with charge $-1.6 imes 10^{-19} \, C$ in a vacuum tube is subjected to a uniform electric field. It accelerates from rest to $2 imes 10^6 \, m/s$ in $0.5 \, \mu s$. The field is then reversed, and the electron continues to move for another $0.5 \, \mu s$. Calculate its average velocity and average speed over the entire duration.

A charged particle in a uniform electric field accelerates from $2 \, m/s$ to $8 \, m/s$ over $3 \, s$. The field direction then reverses. If the particle returns to its initial velocity after another $3 \, s$, what are the average velocity and speed over the $6 \, s$ period?

A toy car experiences a constant acceleration in a straight line, changing its velocity from $4 \, m/s$ to $10 \, m/s$ in $2 \, s$. At this point, the acceleration reverses direction, and the car's velocity returns to $4 \, m/s$ after another $2 \, s$. Determine the car's average speed and average velocity over these $4 \, s$.

A particle moves with a velocity of $5 \, m/s$ for $4 \, s$. Then, it decelerates uniformly to rest in $2 \, s$. Finally, it accelerates uniformly back to its original speed of $5 \, m/s$ in another $2 \, s$. Calculate its average speed and average velocity for the entire $8 \, s$.

An electron falls from rest through a vertical distance $h$ in a uniform and vertically upward directed electric field $E$. Keeping the magnitude of the electric field same, a proton is allowed to fall from rest through the same vertical distance $h$. The time of fall of the electron, in comparison to the time of fall of the proton is:

An alpha particle and a proton are released from rest in a uniform electric field directed vertically upwards. They fall through the same vertical distance $h$. Compare the time of fall of the alpha particle ($t_{\alpha}$) with the time of fall of the proton ($t_p$).

A negatively charged dust particle of mass $m$ and charge $-q$ falls from rest through a vertical distance $h$ in a uniform electric field $E$ directed upwards. What is the time taken for the dust particle to fall this distance?