NEET Physics Units And Measurement MCQs

The viscous force $F$ acting on a sphere of radius $r$ moving with velocity $v$ through a fluid of viscosity $\eta$ is given by $F = 6\pi \eta rv + kr^2v^2$. The dimensions of $k$ are:

The dimensions of coefficient of viscosity are:

The viscous force $F$ acting on a sphere moving through a liquid depends on the radius $r$ of the sphere, the velocity $v$ of the sphere, and the coefficient of viscosity $η$ of the liquid. If $F = kη^arv^b$, where $k$ is a dimensionless constant, using dimensional analysis, find the values of $a$, $b$.

The viscous force $F$ acting on a sphere of radius $r$ moving with velocity $v$ through a fluid of viscosity $\eta$ is given by $F = 6\pi \eta rv$. If a new physical quantity $Q$ is defined as $Q = \frac{Fv^2}{\eta^2 r^3}$, the dimensions of $Q$ are:

Which limitation of dimensional analysis prevents it from deriving the complete formula for the viscous force on a sphere moving through a fluid, given that the force (F) depends on the radius (r) of the sphere, its velocity (v), and the fluid's viscosity ($\eta$)?

“Pascal-Second” has dimension of

The unit of the coefficient of viscosity in S.I. system is

The fundamental unit, which has the same power in the dimensional formulae of surface tension and viscosity is

Which one of the following represents the correct dimensions of the coefficient of viscosity?

The dimensions of Planck’s constant is same as that of